JS内部的Javascript倒计时器+ PHP代码

我需要帮助javascript中的倒数计时器。我在PHPJabbers中找到了下面的代码。 这段代码工作正常，但是当我重新加载页面时，时间会回到初始时间。 即使我加载页面，我也想保留时间。 如果秒== 0我还想在里面添加PHP函数。我不确定它是否可行。 提前致谢

  var seconds = 60; function secondPassed() { var minutes = Math.round((seconds - 30)/60); var remainingSeconds = seconds % 60; if (remainingSeconds < 10) { remainingSeconds = "0" + remainingSeconds; } document.getElementById('countdown').innerHTML = minutes + ":" + remainingSeconds; if (seconds == 0) { clearInterval(countdownTimer); document.getElementById('countdown').innerHTML = "Buzz Buzz"; } else { seconds--; } } var countdownTimer = setInterval('secondPassed()', 1000);  

Answer 1

检查一下，（使用cookies实现）

  function setCookie(cname,cvalue,exdays) { var d = new Date(); d.setTime(d.getTime()+(exdays*24*60*60*1000)); var expires = "expires="+d.toGMTString(); document.cookie = cname + "=" + cvalue + "; " + expires; } function getCookie(cname) { var name = cname + "="; var ca = document.cookie.split(';'); for(var i=0; i 

工作jsFiddle

Answer 2

bhavesh的好解决方案..如果有人想要显示天，小时，分钟，秒，那么他们可以参考这段代码。

 Reverse timer from javascript: var target_date = new Date('Aug 01 2014 20:47:00').getTime(); var days, hours, minutes, seconds; var countdown = document.getElementById('timeremaining'); var countdownTimer = setInterval(function () { var current_date = new Date().getTime(); var seconds_left = (target_date - current_date) / 1000; days = parseInt(seconds_left / 86400); seconds_left = seconds_left % 86400; hours = parseInt(seconds_left / 3600); seconds_left = seconds_left % 3600; minutes = parseInt(seconds_left / 60); seconds = parseInt(seconds_left % 60); if(days <= 0 && hours <= 0 && minutes <= 0 && seconds <= 0 ) { document.getElementById('timeremaining').innerHTML = ''; clearInterval(countdownTimer); } else { if(days>0) { days= days+'d,'; } else { days=''; } countdown.innerHTML ='( ' + days + checkTime(hours) + ':'+ checkTime(minutes) + ':' + checkTime(seconds) +' remaining)'; } }, 1000); function checkTime(i) { if (i < 10) {i = '0' + i}; return i; }