如何使用jQuery.grep（）过滤多维JSON对象

我有一个JSON对象，如下所示：

{"data": [ {"name":"Alan","height":"171","weight":"66"}, {"name":"Ben","height":"182","weight":"90"}, {"name":"Chris","height":"163","weight":"71"} ] ,"school":"Dover Secondary" } 

我想过滤JSON对象以获取高于170且重于70的数据，然后对此对象进行排序。 在jQuery网站上 ，我知道在线性数组上可以很容易地实现过滤，例如：

 arr = jQuery.grep(arr, function(element, index){ return (element > 70 && index = 'weight'); }); 

如何同时过滤重量和高度以获得：

 {"data": [ {"name":"Ben","height":"182","weight":"90"}, ] ,"school":"Dover Secondary" } 

Answer 1

我想你的意思是： http ： //jsfiddle.net/NRuM7/1/ 。

 var obj = {"data": [ {"name":"Alan","height":"171","weight":"66"}, {"name":"Ben","height":"182","weight":"90"}, {"name":"Chris","height":"163","weight":"71"} ] ,"school":"Dover Secondary" }; obj.data = jQuery.grep(obj.data, function(element, index){ return element.weight > 70 && element.height > 170; // retain appropriate elements });