ASP.NET使用ASHX返回JSON

我正在为我的网站创建自动完成function。 到目前为止，javascript部分已经结束了。 此外，我可以获得匹配的用户的MembershipUser对象。

我需要以下列格式返回JSON：

{ query:'Li', suggestions:['Liberia','Libyan Arab Jamahiriya','Liechtenstein','Lithuania'], data:['LR','LY','LI','LT'] } 

这是ashx中的代码：

 public void ProcessRequest (HttpContext context) { System.Web.Script.Serialization.JavaScriptSerializer JsonSerializer; string query = context.Request.QueryString["query"]; System.Web.Security.MembershipUserCollection Users = System.Web.Security.Membership.GetAllUsers(); context.Response.ContentType = "application/json"; foreach (System.Web.Security.MembershipUser User in Users) { if (User.UserName.StartsWith(query.ToLower())) { context.Response.Write(query + Environment.NewLine); context.Response.Write(User.Email); } } } 

如何以所需格式返回json？ 谢谢。

Answer 1

 context.Response.Write( jsonSerializer.Serialize( new { query = "Li", suggestions = new[] { "Liberia", "Libyan Arab Jamahiriya", "Liechtenstein", "Lithuania" }, data = new[] { "LR", "LY", "LI", "LT" } } ) ); 

Answer 2

这有助于我：

 using System; using System.Data; using System.Web; using System.Linq; using System.Collections; using Newtonsoft.Json; public class Handler : IHttpHandler { public void ProcessRequest (HttpContext context) { context.Response.ContentType = "application/json"; string quer = context.Request["query"]; DataTable _t = AMC.Core.Logic.Root.Storage.ExecuteQuery("SELECT [tag_name] FROM [tags] Where [tag_name] like '%' + @ke + '%'", new System.Data.SqlClient.SqlParameter("ke", quer)); DataRow[] list = new DataRow[_t.Rows.Count]; _t.Rows.CopyTo(list, 0); var wapper = new { query = quer , suggestions = (from row in list select row["tag_name"].ToString()).ToArray() //, data = new[] { "LR", "LY", "LI", "LT" } }; context.Response.Write(JsonConvert.SerializeObject(wapper)); } 

Newtonsoft.Json将在这里找到： http ： //json.codeplex.com/releases/

Answer 3

根据所需的返回创建一个具有契约的类，然后在该类的实例上使用JSONSerializer来创建返回内容

 [DataContract] public class YourReturnObject { [DataMember(Name="query")] public String Query { get;set;} [DataMember(Name="suggestions")] public String[] Suggestions { get;set;} [DataMember(Name="data")] public String[] OtherData{ get;set;} } 

Answer 4

你的json有点尴尬，因为你必须维护这两个数组的索引。 我可以建议更像这样的东西吗？

 { query: 'Li', data: [{id:'LR', text:'Liberia'}, {id:'LY', text:'Libyan Arab Jamahiriya'}, ...] }