Ajax调用获取错误

您好我在尝试通过ajax调用传递值时收到错误[object Object]。 我正在使用jquery选择器来获取复选框的值。 并试图通过ajax传递它，这样我只能得到我选择的复选框值。但是得到一个错误。谢谢。 这是我的代码：

dashboard.php

if($param['aktion'] == 'save-widget-vehicle') { $page['register-fahrzeuge'] = array( 1 => array( 'Fahrzeug','aktiv',$page['script'],''), 0 => array( 'Edit-Fahrzeug','enabled',$page['script'],'',''), ); $opts = !empty($param['filterOpts']) ? $param['filterOpts'] : array(); $tmp = array(); foreach ($opts as $opt) { $tmp[] = '"'.$opt.'"'; } $query = 'SELECT Fahrzeuge.dsnr,name FROM Fahrzeuge INNER JOIN ohne_fahrzeuge ON Fahrzeuge.dsnr = ohne_fahrzeuge.dsnr WHERE Fahrzeuge.name IN ('.implode(",", $tmp).')'; $result = mysql_query($query, $myConnection); $data = array(); $html = '
 
 
 
'.CreateRegister($page['register-news']).'
 '.CreateMessage().' 
 '; while($row = mysql_fetch_array($result)){ //$news_result = $fahrzeuge['name']; $html .= ' '; } $html .= '
 
 
  '. $data[] = $row .' 
 
 
 
 
 
'; $return = array( 'status' => 1, 'html' => $html ); echo json_encode($return); die(); $param['aktion'] = 'get-widget-vehicle'; } 

dashboard.js

 function getFahrzeuge() { var opts = []; $("input[type=checkbox]").each(function () { if (this.checked) { opts.push($(this).attr("id")); } }); return opts; } function saveFahrzeugeWidget(opts){ if(!opts || !opts.length){ opts = allFahrzeuge; } $.ajax({ type: "POST", url: "ajax/dashboard.php", dataType : 'json', cache: false, data: {filterOpts: opts, 'aktion' : 'save-widget-vehicle'}, success: function(data){ // $('#fahrzeuge').html(makeTable(records)); $('#fahrzeuge').html(data.html); }, error: function(data){ alert('error' + data); } }); } $('#fahrzeuge .butt-rahmen').live('click', function(){ if($(this).attr('id') == 'submitId') var opts = getFahrzeuge(); saveFahrzeugeWidget(opts); }); var allFahrzeuge = []; $("input[type=checkbox]").each(function(){ allFahrzeuge.push($(this)[0].id) })