如何在jqgrid中填充列表json列表? 列表下的主网格列表是针对子网格的

如何在jqgrid中填充列表json列表? 列表下的主网格列表是针对子网格的,

Jqgrid代码如下,

jQuery("#sg1").jqGrid({ url: 'server.php?q=1', datatype: "json", height: 190, colNames: ['Inv No', 'Date', 'Client', 'Amount', 'Tax', 'Total', 'Notes'], colModel: [{ name: 'id', index: 'id', width: 55 }, { name: 'invdate', index: 'invdate', width: 90 }, { name: 'name', index: 'name', width: 100 }, { name: 'amount', index: 'amount', width: 80, align: "right" }, { name: 'tax', index: 'tax', width: 80, align: "right" }, { name: 'total', index: 'total', width: 80, align: "right" }, { name: 'note', index: 'note', width: 150, sortable: false }], rowNum: 8, rowList: [8, 10, 20, 30], pager: '#psg1', sortname: 'id', viewrecords: true, sortorder: "desc", multiselect: false, subGrid: true, caption: "Custom Icons in Subgrid", // define the icons in subgrid subGridOptions: { "plusicon": "ui-icon-triangle-1-e", "minusicon": "ui-icon-triangle-1-s", "openicon": "ui-icon-arrowreturn-1-e" }, subGridRowExpanded: function(subgrid_id, row_id) { var subgrid_table_id, pager_id; subgrid_table_id = subgrid_id + "_t"; pager_id = "p_" + subgrid_table_id; $("#" + subgrid_id).html("
"); jQuery("#" + subgrid_table_id).jqGrid({ url: "subgrid.php?q=2&id=" + row_id, datatype: "json", colNames: ['No', 'Item', 'Qty', 'Unit', 'Line Total'], colModel: [{ name: "num", index: "num", width: 80, key: true }, { name: "item", index: "item", width: 130 }, { name: "qty", index: "qty", width: 70, align: "right" }, { name: "unit", index: "unit", width: 70, align: "right" }, { name: "total", index: "total", width: 70, align: "right", sortable: false }], rowNum: 20, pager: pager_id, sortname: 'num', sortorder: "asc", height: '100%' }); jQuery("#" + subgrid_table_id).jqGrid('navGrid', "#" + pager_id, { edit: false, add: false, del: false }) } }); jQuery("#sg1").jqGrid('navGrid', '#psg1', { add: false, edit: false, del: false });

列表json的示例列表如下

 [{ "id": "01", "name": "AA", "age": "29", "subData": [{ "id": "01", "name": "AA", "age": "29" }, { "id": "02", "name": "BB", "age": "30" }, { "id": "03", "name": "CC", "age": "31" }, { "id": "04", "name": "DD", "age": "32" }] }, { "id": "02", "name": "BB", "age": "30", "subData": [{ "id": "01", "name": "AA", "age": "29" }, { "id": "02", "name": "BB", "age": "30" }, { "id": "03", "name": "CC", "age": "31" }, { "id": "04", "name": "DD", "age": "32" }] }, { "id": "03", "name": "CC", "age": "31", "subData": [{ "id": "01", "name": "AA", "age": "29" }, { "id": "02", "name": "BB", "age": "30" }, { "id": "03", "name": "CC", "age": "31" }, { "id": "04", "name": "DD", "age": "32" }] }, { "id": "04", "name": "DD", "age": "32", "subData": [{ "id": "01", "name": "AA", "age": "29" }, { "id": "02", "name": "BB", "age": "30" }, { "id": "03", "name": "CC", "age": "31" }, { "id": "04", "name": "DD", "age": "32" }] }] 

Jqgrid给出了基于url的获取数据然后如何将列表列表放到子网格中? 请帮我…..

有不同的方法来实现您的要求。 例如,答案描述了如何根据每个项目的subData部分填充beforeProcessinguserdata 。 我建议您另外阅读答案 ,这似乎可以使您的数据可视化对用户更舒适。