为什么这个jquery ajax调用没有从我的PHP脚本返回数据？
我是jQuery的新手，并且无法在Firebug中调试这个ajax调用：
这是我的ajax电话：
var styndx = $('#studylist option:selected').val(); var studyname = $('#edit_field').val(); $.post("saveStudyName.php", {'type': 'update', 'studyname':studyname, 'styndx':styndx}, function(resultmsg) { $('#edit_field').val(''); $('#savebtn').attr('disabled',true); refresh_studynames(); }); 这是函数refresh_studynames：
function refresh_studynames() { $.ajax({ url: 'getStudyNames.php', data: "", dataType: 'json', error: function() { alert('Refresh of study names failed.'); }, success: function(data) { $data.each(data, function(val, sname) { $('#studylist').append( $('').val(val).html(sname) ) }); } }); }
最后，这是php脚本getStudyNames.php（$ dbname，$ dbconnect，$ hostname全部填充，$ dbconnect工作;后端数据库是Postgres， pg_fetch_all是PHP中的Postgres函数，它返回结果作为数组）：
$dbconnect = pg_pconnect("host=".$hostname." user=".$dbuser." dbname=".$dbname); if (!$dbconnect) { showerror(0,"Failed to connect to database",'saveStudyName',30,"username=".$dbuser.", dbname=".$dbname); exit; } $sql = "SELECT ST.studyindex,ST.studyabrv AS studyname FROM ibg_studies ST ORDER BY studyname"; $fetchresult = pg_exec($dbconnect, $sql); if ($fetchresult) { $array = pg_fetch_all($fetchresult); echo json_encode($array); } else { $msg = "Failure! SQL="+$sql; echo $msg; }
任何帮助非常感谢….
这条线
$('#studylist').append( $('').val(val).html(sname) );
看起来不对劲
我不太确定你可以尝试：
var $studylist = $('#studylist').empty(); $data.each(data, function(i, record) { $studylist.append( $('').html(record.sname) ); });