如何展平对象的文字属性？

我有一个遗留服务器返回的对象，我想通过JavaScript，jQuery甚至Underscore.js更改客户端的结构。

以下是我原始对象的样子：

[ { "Id":{ "LValue":1, "Value":1 }, "Date":{ "LValue":"2013-10-17T00:00:00", "Value":"2013-10-24T00:00:00" }, "User":{ "LValue":508, "Value":507 }, "Comments":{ "LValue":"This a test load", "Value":"This a test" }, "Name":"John Doe", "IsDeleted":false } ] 

但是在客户端，我想将它变平以获得“值”并将“LValues”填充到一个单独的属性中，所以如果我以后需要它，我不会松开它们：

 [ { "Id":1, "Date":"2013-10-24T00:00:00", "User":507, "Comments":"This a test", "Name":"John Doe", "IsDeleted":false, "LValues": { "Id":1, "Date":"2013-10-17T00:00:00", "User":508, "Comments":"This a test load" } } ] 

这将使对象的使用变得更加容易，任何帮助都将深深感激！

Answer 1

 var oList = [ { "Id":{ "LValue":1, "Value":1 }, "Date":{ "LValue":"2013-10-17T00:00:00", "Value":"2013-10-24T00:00:00" }, "User":{ "LValue":508, "Value":507 }, "Comments":{ "LValue":"This a test load", "Value":"This a test" }, "Name":"John Doe", "IsDeleted":false } ]; var newFormat = _(oList).map(function(o) { var flattened = { LValues: {} }; _(o).each(function(val, propName) { flattened[propName] = val.Value ? val.Value : val; if(val.LValue) { flattened.LValues[propName] = val.LValue; } }); return flattened; } 

Answer 2

您可以使用基本的Javascript地图。 假设硬编码属性：

 var flattenedItems = items.map(function(x) { return { Id: x.Id.Value, Date: x.Date.Value, User: x.User.Value, Comments: x.Comments.Value, Name: x.Name, IsDeleted: x.IsDeleted, LValues: { Id: x.Id.LValue, Date: x.Date.LValue, User: x.User.LValue, Comments: x.Comments.LValue, } }; }); 

（小提琴）

如果属性是可变的，那么您可以在map迭代器中迭代它们：

 var flattenedItems = items.map(function(x) { var flattened = { LValues: {} }; for (var prop in x) { flattened[prop] = x[prop].Value; flattened.LValues[prop] = x[prop].LValue; }; return flattened; }); 

（小提琴）

Answer 3

你可以用

 var items = [ { "Id":{ "LValue":1, "Value":1 }, // ... } ]; items = items[0]; var obj = {LValues: {}}; for(var i in items) { if(typeof items[i] === 'object') { obj[i] = items[i].Value; obj.LValues[i] = items[i].LValue; } else { obj[i] = items[i]; } } 

Answer 4

我相信输出实际上是写一个简单的函数

 function flatten(obj){ var r = {}; if(obj){ console.log(obj); r.Id = obj.Id.Value; r.Date = obj.Date.Value; r.User = obj.User.Value; r.Comments = obj.Comments.Value; r.Name = obj.Name.Value; r.IsDeleted = obj.IsDeleted; r.LValues = {}; r.LValues.Id = obj.Id.LValue; r.LValues.Date = obj.Date.LValue; r.LValues.User = obj.User.LValue; r.LValues.Comments = obj.Comments.LValue; } return r; }