将数据从knockout.js发布到CakePHP控制器

我正在将knockout.js页面中的数据发布到cakephp中的控制器，并且它表示数据已成功发布，但是，我的控制器似乎没有响应，我也没有收到警报……甚至没有空响应。 我甚至检查了chrome中的网络选项卡，它显示了正确的POSTED数据

这是从我的knockout viewmodel文件发布的数据

var JSON_order = JSON.stringify({"orderInfo":[{"itemNumber":"1","quantity":"1","price":1.00,"productName":"test"}]}); $.post("/orders/submit_order", JSON_order, function(data){ alert(data.check); //alert doesn't appear }, "json"); 

这是我的控制器

 function submit_order(){ $this->layout = false; $this->autoRender = false; if ($this->request->is('post')) { $order = $this->request->data; $order = json_decode($order, true); $finalize_order = new submit; $finalize_order->display_submitted_order_success($order); } } 

这是display_submitted_order_success的代码（我也在CakePHP之外的php文件上尝试了这个，但它也没有用）

 function display_submitted_order_success($order = null){ $this->layout = false; $this->autoRender = false; //I'm just trying to display the order as-is so that I know it's even being posted to begin with echo json_encode(array("check" => "success","order_num" => $order)); //the values passed the price check, display the result } 

Answer 1

您必须将JSON_order的值JSON_order var：

 var JSON_order = JSON.stringify({"orderInfo":[{"itemNumber":"1","quantity":"1","price":1.00,"productName":"test"}]}); $.post("/orders/submit_order", {order:JSON_order}, function(data){ alert(data.check); //alert doesn't appear }, "json"); 

这样你的控制器会像这样接收它：

 $data['order'] = '{"orderInfo":[{"itemNumber":"1","quantity":"1","price":1,"productName":"test"}]}'