使用Json将带有两个对象的viewmodel传递给控制器

这是我的代码。 下面的JSON不正确但我认为我很接近。 控制器每次都获取空数据。 任何帮助，将不胜感激。

$( "#btnRegister" ).click(function() { var personModel = { FirstName: $("#txtFirstName").val(), LastName: $("#txtLastName").val(), Phone: $("#txtPhone").val(), EmailAddress: $("#txtEmail").val() }; var loginModel = { UserName: $("#txtUserName").val(), Password: $("#txtPassword").val() }; var registerViewModel = { WebUser: loginModel, Person: personModel }; $.ajax({ url: "@Url.Action("Register", "User")", type: 'POST', data: registerViewModel, success: function(result) { alert(result); } }); }); [HttpPost] public JsonResult Register(RegisterViewModel registerViewModel) { string name = registerViewModel.Person.FirstName; string username = registerViewModel.WebUser.UserName; return Json(name); } public class RegisterViewModel { public WebUser WebUser { get; set; } public Person Person { get; set; } } public class WebUser { [Key] public string UserId { get; set; } public string UserName { get; set; } public string Password { get; set; } } public class Person { [Key] public int PersonId { get; set; } public string FirstName { get; set; } public string LastName { get; set; } public string Phone { get; set; } public string EmailAddress { get; set; } public string EmailConfirmation { get; set; } public DateTime DateCreated { get; set; } public string UserId { get; set; } } 

Answer 1

ajax部分需要像这样

  $.ajax({ url: "@Url.Action("Register", "User")", type: 'POST', contentType: "application/json; charset=utf-8", data: JSON.stringify(registerViewModel), success: function(result) { alert(result); } }); 

希望这可以帮助！

Answer 2

您似乎缺少正在搜索的ID前面的哈希值，除了

 $("#txtFirstName").val(),