Laravel 5：如何分析Ajax响应

我正在进行搜索并基于此我通过Jquery-Ajax返回一些数据显示数据没有问题，但我需要它们作为分页。

JQuery的

$(document).ready( function() { $(".client_search_option").change(function(){ var selectedClientTypeVal = ""; var selectedSmsDecisionVal = ""; var selectedClientType = $('input[type=radio][name=clientType]:checked'); var selectedSmsDecision = $('input[type=radio][name=sms_decision]:checked'); if (selectedClientType.length > 0) { selectedClientTypeVal = selectedClientType.val(); } if (selectedSmsDecision.length > 0) { selectedSmsDecisionVal = selectedSmsDecision.val(); } //alert(selectedClientTypeVal); //alert(selectedSmsDecisionVal); var CSRF_TOKEN = $('meta[name="csrf-token"]').attr('content'); $.ajax({ url: 'http://localhost/pages/clientSearchAjax', type: 'POST', data: {_token: CSRF_TOKEN, selectedClientTypeVal:selectedClientTypeVal,selectedSmsDecisionVal:selectedSmsDecisionVal}, dataType: 'JSON', success: function (data) { console.log(data); }, error:function(){ alert("An error has occured !"); } }); }); }); 

调节器

 public function clientSearch(){ $client_option = Input::get('selectedClientTypeVal'); $sms_option = Input::get('selectedSmsDecisionVal'); if($client_option == 'all' && $sms_option == 'all'){ $ajax_clients = Client::with('clientType')->paginate(5); }else{ $ajax_clients = Client::with('clientType')->where('clienttype_id', $client_option)->where('send_sms', $sms_option)->paginate(5); } return $ajax_clients->toJson(); } 

我如何分页这个Ajax响应，任何帮助将不胜感激。

Answer 1

我处于相同的情况，经过一番研究后，我发现了以下链接。 可能这可以帮到你。

控制器方法

 public function showPosts() { $posts = Post::paginate(5); if (Request::ajax()) { return Response::json(View::make('posts', array('posts' => $posts))->render()); } return View::make('blog', array('posts' => $posts)); } 

jQuery Part

检查此链接