jstree获取所选节点的级别

如何获得当前所选节点的学位/级别？ 即它拥有的父母数量。

我有一节在选择节点时执行：

.bind("select_node.jstree", function (event, data) { var nodeInfo = $("#" + data.rslt.obj.attr("id")); console.log(data.rslt.obj.attr("id")); // the id of the node console.log(nodeInfo.children("a").text()); // the name of the node // the level of the node??? }); 

Answer 1

data.inst.get_path().length

1是根节点;

 .bind("select_node.jstree",function(e,data) { var inst=data.inst; var level=inst.get_path().length; var selected=inst.get_selected(); var id=selected.attr('id'); var name=selected.prop('tagName'); console.log(name,id,level); }); 

（最好使用inst，而不是用dom搜索）;

 $(function () { $("#demo1").jstree({ "plugins" : [ "themes", "html_data", "ui", "cookies" ] }); $("#demo2").jstree({ "plugins" : [ "themes", "html_data", "ui", "cookies" ] }); $('#demo1,#demo2').bind("select_node.jstree",function(e,data) { var inst=data.inst; var level=inst.get_path().length; var selected=inst.get_selected(); var id=selected.attr('id'); var name=selected.prop('tagName'); console.log(name,id,level); }); }); 

    With id-s: 
 
 
 Root node 1 
 
 Child node 1 
 
 Child node 2 
 
 
 
 Root node 2 
 
 
 Without id-s: 
 
 
 Root node 1 
 
 Child node 1 
 
 Child node 2 
 
 
 
 Root node 2 
 
  

Answer 2

你也可以使用（在jstree 3.1.0中）：

 .bind("select_node.jstree",function(e,data) { var level=data.node.parents.length; // 1 = root level, 2 = next level down, etc }); 

Answer 3

 .bind("select_node.jstree", function(e, data) { var level = data.node.parents.length; var text = data.node.text; var id = data.node.id; console.log(level,text,id); }) ;