如何通过asp.net MVC 4中的ajax请求下载文件

以下是我的代码：

ActionResult DownloadAttachment(student st) { var file = db.EmailAttachmentReceived.FirstOrDefault(x => x.LisaId == st.Lisaid); byte[] fileBytes = System.IO.File.ReadAllBytes(file.Filepath); return File(fileBytes, System.Net.Mime.MediaTypeNames.Application.Octet, file.Filename); } 

这是我正在使用的脚本

 $(function () { $("#DownloadAttachment").click(function () { $.ajax({ url: '@Url.Action("DownloadAttachment", "PostDetail")', contentType: 'application/json; charset=utf-8', datatype: 'json', type: "GET", success: function () { alert("sucess"); } }); }); }); 

如何返回文件下载追求上面的代码？

Answer 1

请在ajax成功中试试这个

 success: function () { window.location = 'https://stackoverflow.com/questions/30704078/how-to-download-a-file-through-ajax-request-in-asp-net-mvc-4/@Url.Action("DownloadAttachment", "PostDetail")'; } 

更新的答案：

 public ActionResult DownloadAttachment(int studentId) { // Find user by passed id // Student student = db.Students.FirstOrDefault(s => s.Id == studentId); var file = db.EmailAttachmentReceived.FirstOrDefault(x => x.LisaId == studentId); byte[] fileBytes = System.IO.File.ReadAllBytes(file.Filepath); return File(fileBytes, System.Net.Mime.MediaTypeNames.Application.Octet, file.Filename); } 

Ajax请求：

 $(function () { $("#DownloadAttachment").click(function () { $.ajax( { url: 'https://stackoverflow.com/questions/30704078/how-to-download-a-file-through-ajax-request-in-asp-net-mvc-4/@Url.Action("DownloadAttachment", "PostDetail")', contentType: 'application/json; charset=utf-8', datatype: 'json', data: { studentId: 123 }, type: "GET", success: function () { window.location = 'https://stackoverflow.com/questions/30704078/how-to-download-a-file-through-ajax-request-in-asp-net-mvc-4/@Url.Action("DownloadAttachment", "PostDetail", new { studentId = 123 })'; } }); }); }); 

Answer 2

我认为不需要Ajax调用你可以简单地使用超链接 ，如下例所示。

查看代码

 Download Form 

控制器方法

 public ActionResult DownloadAttachment(int studentId) { // Find user by passed id var file = db.EmailAttachmentReceived.FirstOrDefault(x => x.LisaId == studentId); byte[] fileBytes = System.IO.File.ReadAllBytes(file.Filepath); return File(fileBytes, System.Net.Mime.MediaTypeNames.Application.Octet, file.Filename); } 

Answer 3

下面的方法将有助于从jQuery对话框窗口调用Ajax请求中的操作并执行操作，并且可以在操作返回成功结果后立即关闭对话框窗口

调节器

  [HttpGet] public ActionResult DownloadCampaign(string filePath, string mode) { string contentType = string.Empty; var sDocument = filePath; if (!System.IO.File.Exists(sDocument)) { return HttpNotFound(); } if (mode == "action") return Json(new {fileName = filePath}, JsonRequestBehavior.AllowGet); if (sDocument.Contains(".pdf")) { contentType = "application/pdf"; } else if (sDocument.Contains(".docx")) { contentType = "application/docx"; } else if (sDocument.Contains(".xls")) { contentType = "application/xlsx"; } return File(sDocument, contentType, sDocument); } 

JQuery – Ajax请求

 $(document) .ready(function() { $("#btnDownload").click(function () { var file = $("#FilePath").val(); $.ajax({ url: 'https://stackoverflow.com/questions/30704078/how-to-download-a-file-through-ajax-request-in-asp-net-mvc-4/@Url.Action("DownloadCampaign", "FileList")', data: { filePath: file, mode:'action' }, method: 'GET', dataType: 'json', //contentType: 'application/json; charset=utf-8', success: function(data) { @*window.location = '@Url.RouteUrl("DownloadCampaign", "FileList", new { filePath = data1.fileName })';*@ window.location.href = "@Url.RouteUrl(new { Controller = "FileList", Action = "DownloadCampaign" })/?filePath=" + data.fileName + "&mode=download"; $("#downloadFile_dialog").dialog("close"); }, error: function (req, status, errorObj) { alert("Error"); } }); }); }); 

如果您需要更多相关信息，请与我联系。

Answer 4

 public FileResult DownloadGeneralDocs(string docName) { string fileName = docName+".pdf"; var path = _globalWebSettings.Value.DownloadGeneralDocsPath; string filePath = ""; if (fileName!="") { filePath = (_env.WebRootPath + string.Format("{0}{1}",path, fileName)); } FileInfo file1 = new FileInfo(filePath); byte[] fileBytes = System.IO.File.ReadAllBytes(file1.FullName); return File(fileBytes, System.Net.Mime.MediaTypeNames.Application.Octet, fileName); } view.cshtml: