根据日期和时间对JSON数据进行排序

是否可以使用jQuery / Javascript根据时间（2016-12-07T13：00：00）重新排列以下JSON格式。

[ { "id":1, "start":"2016-12-07T13:00:00", "subject":"test1", }, { "id":2, "start":"2016-12-07T09:00:00", "subject":"test2", }, { "id":3, "start":"2016-12-07T10:00:00", "subject":"test3", }, { "id":4, "start":"2016-12-07T07:00:00", "subject":"test4", }, { "id":5, "start":"2016-12-07T14:00:00", "subject":"test5", } ] 

Answer 1

您可以在属性start的排序回调中使用String#localeCompare ，因为ISO 8601日期可以排序为字符串。

 var array = [ { id: 1, start: "2016-12-07T13:00:00", subject: "test1" }, { id: 2, start: "2016-12-07T09:00:00", subject: "test2" }, { id: 3, start: "2016-12-07T10:00:00", subject: "test3" }, { id: 4, start: "2016-12-07T07:00:00", subject: "test4" }, { id: 5, start: "2016-12-07T14:00:00", subject: "test5" } ]; array.sort(function (a, b) { return a.start.localeCompare(b.start); }); console.log(array); 

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Answer 2

如果您可以使用外部库例如Lodash

https://lodash.com/

将json字符串分配给变量并尝试

 var sort = _.sortBy(variable_name, "start") 

希望这有助于你。

Answer 3

是的，您将使用javascript数组排序方法（ http://www.w3schools.com/jsref/jsref_sort.asp ）。

将数组定义为将其赋值给变量然后调用sort方法，您可以将sort方法传递给函数以执行比较的详细信息。

  var aryData = [{"id":1 ,"start":"2016-12-07T13:00:00" ,"subject":"test1" },{ "id":2 ,"start":"2016-12-07T09:00:00" ,"subject":"test2" },{ "id":3 ,"start":"2016-12-07T10:00:00" ,"subject":"test3" },{ "id":4 ,"start":"2016-12-07T07:00:00" ,"subject":"test4" },{ "id":5 ,"start":"2016-12-07T14:00:00" ,"subject":"test5" }]; aryData.sort(function(a, b) { var dtA = new Date(a['start']) ,dtB = new Date(b['start']); return ( dtA.getTime() - dtB.getTime() ); }); 

Answer 4

试试这个可能有帮助，

 var aryData =[ { "id":1, "start":"2016-12-07T13:00:00", "subject":"test1", }, { "id":2, "start":"2016-12-07T09:00:00", "subject":"test2", }, { "id":3, "start":"2016-12-07T10:00:00", "subject":"test3", }, { "id":4, "start":"2016-12-07T07:00:00", "subject":"test4", }, { "id":5, "start":"2016-12-07T14:00:00", "subject":"test5", } ]; function comp(a, b) { return new Date(a.start).getTime() - new Date(b.start).getTime(); } aryData.sort(comp); console.log(aryData); 

Answer 5

 //put to variable var db = [ { "id":1, "start":"2016-12-07T13:00:00", "subject":"test1", }, { "id":2, "start":"2016-12-07T09:00:00", "subject":"test2", }, { "id":3, "start":"2016-12-07T10:00:00", "subject":"test3", }, { "id":4, "start":"2016-12-07T07:00:00", "subject":"test4", }, { "id":5, "start":"2016-12-07T14:00:00", "subject":"test5", } ]; //use .sort() db.sort( function(a,b){ //use new Date parse string to date type //convert date to number use Date.parse() //format function(a,b) { return ab; } return Date.parse(new Date(a.start)) - Date.parse(new Date(b.start)); } ); console.log(db)