将对象数据从AJAX发送到PHP

我正在尝试将数据发送到php文件以保存在数据库中，但我没有任何响应。 如果选中复选框，则[obj] [idCheckbox] = 1，否则[obj] [idCheckbox] = 0。

发送的文件

var i=0; var objetoTodasPermissoes = function(){}; var objTodasPermissoes = new objetoTodasPermissoes(); $.each($(".classePermissoes"), function(){ objTodasPermissoes[$(this)[0].id] = 0 i++; }); $.each($(".classePermissoes:checked"), function(){ alert('ok'); objTodasPermissoes[$(this)[0].id] = 1; }); console.log(objTodasPermissoes); $.each($("#userList tr"),function(){ alert(this.id); var iduser = this.id; $.ajax({ url:'../json/usuarioperm/savePermissions.php', data:({ idusuario:iduser, objTodasPermissoes:objTodasPermissoes, }), success:function(a){ Alert("Saved!"); } }); }); } 

savePermissions.php文件。

  $iduser = $_POST["iduser"]; $perm_usuarios = $_POST["objTodasPermissoes"]["perm_usuarios"]; $perm_importar = $_POST["objTodasPermissoes"]["perm_importar"]; $perm_log = $_POST["objTodasPermissoes"]["perm_log"]; $perm_proto = $_POST["objTodasPermissoes"]["perm_proto"]; $perm_limpeza = $_POST["objTodasPermissoes"]["perm_limpeza"]; $perm_lixeira = $_POST["objTodasPermissoes"]["perm_lixeira"]; $perm_relatusuarios = $_POST["objTodasPermissoes"]["perm_relatusuarios"]; $perm_deptos = $_POST["objTodasPermissoes"]["perm_deptos"]; $perm_deptospastas = $_POST["objTodasPermissoes"]["perm_deptospastas"]; $perm_empresas = $_POST["objTodasPermissoes"]["perm_empresas"]; mysql_query("UPDATE hospital.users set perm_usuarios=".$perm_usuarios.", perm_importar=".$perm_importar.", perm_log=".$perm_log.", perm_proto=".$perm_proto.", perm_limpeza=".$perm_limpeza.", perm_lixeira=".$perm_lixeira.", perm_relatusuarios=".$perm_relatusuarios.", perm_deptos=".$perm_deptos.", perm_deptospastas=".$perm_deptospastas.", perm_empresas=".$perm_empresas." where id=".$iduser) or die (mysql_error()); 

谢谢。

Answer 1

PHP很有趣，因为当涉及到Ajax时，它不像其他表单那样从$_POST提取。 您实际上需要从php://input读取php://input

这是一个很小的例子

 $data = file_get_contents("php://input"); $response = json_decode($data, true ); // True converts to array; blank converts to object $emailAddr = $response["email"]; 

希望你能成功申请。

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编辑：您可以添加filter_var命令来删除不良字符并清理输入。

 $emailAddr = filter_var($response["email"], FILTER_SANITIZE_EMAIL); $firstName = filter_var($response["firstName"], FILTER_SANITIZE_STRING); 

在调试时我强烈建议使用Chrome的开发者模式和“网络”标签。 在底部附近找到您的ajax电话，您可以查看确切的标题信息。