如何从此对象中检索Constituency_Name

如何从此对象中检索Constituency_Name 。

 [{"Constituency_ID":148,"Constituency_Name":"NA-160"}, {"Constituency_ID":151,"Constituency_Name":"NA-163"}, {"Constituency_ID":149,"Constituency_Name":"NA-161"}, {"Constituency_ID":150,"Constituency_Name":"NA-162"}] 

 data: { Constituency_ID: Constituency_Name }, success: function (cities) $('#Constituency_ID').html(""); 

 $.each(cities, function (key, value) { var a = cities.length; var we= value[0].map(function (element, index) { return element.Constituency_Name; }) ///parsedData var select = document.getElementById('#Constituency_ID'); // var pos =value[0].Constituency_Name.indexOf("NA"); option = document.createElement('option'); option.text = we; option.value = value[0].Constituency_ID; $('#Constituency_ID').append(option); }); } }); } 

Answer 1

  var p = [{"Constituency_ID":148,"Constituency_Name":"NA-160"},{"Constituency_ID":151,"Constituency_Name":"NA-163"},{"Constituency_ID":149,"Constituency_Name":"NA-161"},{"Constituency_ID":150,"Constituency_Name":"NA-162"}] var countryNameArray = p.map(function(element,index){ return element.Constituency_Name; }) console.log(countryNameArray[0]) // prints NA-160 

Answer 2

这应该可以解决您的问题

  cities.forEach(function(element,index{ $('#Constituency_ID').append(''+element.Constituency_Name+ '') }) 

如果您想为您的选项增加价值，请使用此选项

 cities.forEach(function(element,index{ $('#Constituency_ID').append(''+element.Constituency_Name+ '') })