Django ajax HttpResponse json错误意外的令牌d

我正在尝试使用媒体编辑器做一个Django ajax HttpResponse json。

view.py

def test(request, union_id): if request.is_ajax(): t = Union.objects.get(id=union_id) message = json.loads(request.body) t.description = message['description']['value'] t.save() return HttpResponse(message, mimetype="application/json") else: message = "Not Ajax" return HttpResponse(message) 

Jquery（更新）

  function getCookie(name) { var cookieValue = null; if (document.cookie && document.cookie != '') { var cookies = document.cookie.split(';'); for (var i = 0; i < cookies.length; i++) { var cookie = jQuery.trim(cookies[i]); // Does this cookie string begin with the name we want? if (cookie.substring(0, name.length + 1) == (name + '=')) { cookieValue = decodeURIComponent(cookie.substring(name.length + 1)); break; } } } return cookieValue; } var csrftoken = getCookie('csrftoken'); function csrfSafeMethod(method) { // these HTTP methods do not require CSRF protection return (/^(GET|HEAD|OPTIONS|TRACE)$/.test(method)); } $.ajaxSetup({ crossDomain: false, // obviates need for sameOrigin test beforeSend: function(xhr, settings) { if (!csrfSafeMethod(settings.type)) { xhr.setRequestHeader("X-CSRFToken", csrftoken); } } }); $('#savecontentObj').click(function() { var contentObj = editor.serialize(); obj = JSON.stringify(contentObj); $.ajax({ url:"update", type: "POST", data: obj, dataType: "json", contentType: "application/json", success:function(response){ console.log('success'); }, complete:function(){ console.log('complete'); }, error:function (xhr, textStatus, thrownError){ console.log(thrownError); console.log(obj); } }); }); 

的console.log

 SyntaxError {stack: (...), message: "Unexpected token d"} {"description":{"value":"
dddddd
"}} complete 

它将“描述”保存到数据库，但我没有在httpresponse中取得成功，正如您在console.log中看到的那样。

非常感谢！

更新

url.py

 url(r'^(?P\d+)/update$', views.test), 

Answer 1

 def test(request, union_id): if request.is_ajax(): t = Union.objects.get(id=union_id) t.description = request.POST.get('description',None) t.save() HttpResponse(json.dumps(dict(status='updated')), mimetype="application/json") else: message = "Not Ajax" HttpResponse(json.dumps(dict(status="Not Ajax")), mimetype="application/json") $('#savecontentObj').click(function() { var contentObj = editor.serialize(); $.ajax({ url:"update", type: "POST", data: contentObj, dataType: "json", success:function(data){ console.log(data.success); }, complete:function(){ console.log('complete'); }, error:function (xhr, textStatus, thrownError){ console.log(thrownError); console.log(obj); } }); }); 

确保您的ajaxurl不符合您的视图方法，并且csrf标记必须存在于序列化值中。